# Min Cost to Connect All Points

published on 4/25/2022You are given an array points representing integer coordinates of some points on a 2D-plane, where points[i] = [xi, yi].

The cost of connecting two points [xi, yi] and [xj, yj] is the manhattan distance between them: |xi - xj| + |yi - yj|, where |val| denotes the absolute value of val.

Return the minimum cost to make all points connected. All points are connected if there is exactly one simple path between any two points.

Input: points = [[0,0],[2,2],[3,10],[5,2],[7,0]]

Output: 20

## Explanation:

We can connect the points as shown above to get the minimum cost of 20. Notice that there is a unique path between every pair of points.

Constraints:

1 <= points.length <= 1000 -106 <= xi, yi <= 106 All pairs (xi, yi) are distinct.

class Solution:def minCostConnectPoints(self, points: List[List[int]]) -> int:d, res = {(x, y): float('inf') if i else 0 for i, (x, y) in enumerate(points)}, 0while d:x, y = min(d, key=d.get) # obtain the current minimum edgeres += d.pop((x, y)) # and remove the corresponding pointfor x1, y1 in d: # for the rest of the points, update the minimum manhattan distanced[(x1, y1)] = min(d[(x1, y1)], abs(x-x1)+abs(y-y1))return res

## Code walkthrough

Simple MST approch to solve approch to solve this problem.